过滤

_.where(list, properties)

遍历list中的每一个值，返回一个数组，这个数组包含properties所列出的属性的所有的 键 - 值对。

    var list = [
        {title:"AAA",year: 1982},
        {title:"BBB",year: 1900},
        {title:"CCC",year: 1982}
    ];
    console.log(
        _.where(list,{year: 1982})
    );
    => [ { title: 'AAA', year: 1982 }, { title: 'CCC', year: 1982 } ]